Quake3World

is this the correct way to calculate a gradient between points ?

double aaa=0.00, bbb=0.00;
aaa= y2-y1;
bbb= x2-x1;

gradient = aaa/bbb;

?

ty

the math is correct for the slope between (x1,y1) and (x2,y2) if that's what you're asking.

thats it thanks mate

cheers

Or you could save some lines and just do;
gradient = y2-y1/x2-x1;

he might need the aaa and bbb later.

what has this to do with c++?

menkent wrote:the math is correct for the slope between (x1,y1) and (x2,y2) if that's what you're asking.

Save that he doesn't check for division by zero.

PhoeniX wrote:Or you could save some lines and just do;
gradient = y2-y1/x2-x1;

well, since one might just "copy" the above, i think the above is not correct.

to be specific, it would equal to

gradient = y2 - (y1/x2) - x1 when he really wants

gradient = (y2-y1) / (x2-x1);

Hey guys can you help me with an ASP.NET problem?

What is the formula to find the midpoint of a line?

line divided by two

new question

how would i calculate the intercept of Y ?