This is rather cool
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This is rather cool
http://tinyurl.com/bjcl5
A lot of potential applications for this thing, besides picking up chicks. The Mobile Infantry is not far off.
A lot of potential applications for this thing, besides picking up chicks. The Mobile Infantry is not far off.
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These have been in development on and off since the 60s.
I don't see a large battery anywhere on the suit.I'm interested in what sort of power source it has. That's one of the big problems with suits/exoskeletons like this, regular batteries are large and heavy.
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I wouldn't imagine very high at all. Seems to me that the actuators would have to move VERY quickly to accomplish a high jump, and when you're trying to give a large boost in lifting power, you wouldn't necessarily design it that way. I could be wrong, though.Kracus wrote:I'm interested in how high I can jump with one of those mofos.
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I saw the prototype for this thing a few years ago. Pretty much the same thing except they made this version smaller and there aren't a huge mess of wires running all over the place.
It is not very fast so you definitely won't be able to jump very high if at all (due to the weight), it basically helps a person lift things that would normally be relatively heavy.
It is not very fast so you definitely won't be able to jump very high if at all (due to the weight), it basically helps a person lift things that would normally be relatively heavy.
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i haven't been at school for almost 5 days now, so the lack of learning requires that i flex my brain muscles with this:Kracus wrote:I'm interested in how high I can jump with one of those mofos.
if the suit enhances your jump/strength by 1.5 times (for example, it's probably lower though)
on a 70kg person:
Funaided = 200 N = ma = 70a
aunaided = 200/70 = 2.86 m/s upward
add on the 15kg of machine:
Faided = (200*1.5) N = (70+15)a
aaided = (200*1.5)/(70+15) = 300/85 = 3.53 m/s upward
the heights of your jumps become: (x is displacement/height)
formula: v^2 = u^2 + 2ax
(v = final velocity = 0; u = initial = acceleration above; a = gravitational acceleration = 9.8 m/s downward)
therefore: x = -u^2/(2a) = -u^2/(2×-9.8) = u^2/19.6
xunaided = (2.86)^2/19.6 = 0.42 meters or 1.37 feet.
xaided = (3.53)^2/19.6 = 0.64 meters or 2.09 feet.
so there you go
